(2x)^2/(0.0175-x)(0.0175-x)=56

Solution for (2x)^2/(0.0175-x)(0.0175-x)=56 equation:

(2x)^2/(0.0175-x)(0.0175-x)=56

We move all terms to the left:

(2x)^2/(0.0175-x)(0.0175-x)-(56)=0


Domain of the equation: (0.0175-x)(0.0175-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.0175-x!=-0.0175

x∈R


We add all the numbers together, and all the variables

2x^2/(-1x+0.0175)(-1x+0.0175)-56=0

We multiply parentheses ..

2x^2/(+x^2-0.0175x-0.0175x+0.00030625)-56=0

We multiply all the terms by the denominator


2x^2-56*(+x^2-0.0175x-0.0175x+0.00030625)=0

We multiply parentheses

2x^2-56x^2-0x-0x-0.01715=0

We add all the numbers together, and all the variables

-54x^2-2x-0.01715=0

a = -54; b = -2; c = -0.01715;
Δ = b2-4ac
Δ = -22-4·(-54)·(-0.01715)
Δ = 0.2956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{0.2956}}{2*-54}=\frac{2-\sqrt{0.2956}}{-108}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{0.2956}}{2*-54}=\frac{2+\sqrt{0.2956}}{-108}
$